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Tune FAR aggregation #49581

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Merged
Andrew Casey (amcasey) merged 4 commits into from
Jun 16, 2022
+26 −16
Merged

Tune FAR aggregation #49581

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58a4aad
Tune FAR aggregation
amcasey Jun 16, 2022
f3a41fc
Add missing null-checks
amcasey Jun 16, 2022
a12e29e
Fix lint errors
amcasey Jun 16, 2022
7f1e10c
Remove redundant null checks and unreachable case
amcasey Jun 16, 2022
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42 changes: 26 additions & 16 deletions src/server/session.ts
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Original file line number Diff line number Diff line change
Expand Up @@ -380,7 +380,7 @@ namespace ts.server {
// correct results to all other projects.

const defaultProjectResults = perProjectResults.get(defaultProject);
if (defaultProjectResults?.[0].references[0]?.isDefinition === undefined) {
if (defaultProjectResults?.[0]?.references[0]?.isDefinition === undefined) {
// Clear all isDefinition properties
perProjectResults.forEach(projectResults => {
for (const referencedSymbol of projectResults) {
Expand Down Expand Up @@ -531,26 +531,35 @@ namespace ts.server {
defaultDefinition :
defaultProject.getLanguageService().getSourceMapper().tryGetSourcePosition(defaultDefinition!));

// Track which projects we have already searched so that we don't repeat searches.
// We store the project key, rather than the project, because that's what `loadAncestorProjectTree` wants.
// (For that same reason, we don't use `resultsMap` for this check.)
const searchedProjects = new Set<string>();
// The keys of resultsMap allow us to check which projects have already been searched, but we also
// maintain a set of strings because that's what `loadAncestorProjectTree` wants.
const searchedProjectKeys = new Set<string>();

onCancellation:
while (queue.length) {
while (queue.length) {
if (cancellationToken.isCancellationRequested()) break onCancellation;

let skipCount = 0;
for (; skipCount < queue.length && resultsMap.has(queue[skipCount].project); skipCount++);
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if (skipCount === queue.length) {
queue.length = 0;
break;
}

if (skipCount > 0) {
queue.splice(0, skipCount);
}

// NB: we may still skip if it's a project reference redirect
const { project, location } = queue.shift()!;

@DanielRosenwasser Daniel Rosenwasser (DanielRosenwasser) Jun 21, 2022

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Would it make more sense long-term not to de-queue at all? Just iterate through and toss the array at the end?

@DanielRosenwasser Daniel Rosenwasser (DanielRosenwasser) Jun 21, 2022

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I guess not, then it would just get longer and longer.


if (isLocationProjectReferenceRedirect(project, location)) continue;

if (!tryAddToSet(searchedProjects, getProjectKey(project))) continue;

const projectResults = searchPosition(project, location);
if (projectResults) {
resultsMap.set(project, projectResults);
}
resultsMap.set(project, projectResults ?? emptyArray);
searchedProjectKeys.add(getProjectKey(project));
}

// At this point, we know about all projects passed in as arguments and any projects in which
Expand All @@ -559,10 +568,10 @@ namespace ts.server {
// containing `initialLocation`.
if (defaultDefinition) {
// This seems to mean "load all projects downstream from any member of `seenProjects`".
projectService.loadAncestorProjectTree(searchedProjects);
projectService.loadAncestorProjectTree(searchedProjectKeys);
projectService.forEachEnabledProject(project => {
if (cancellationToken.isCancellationRequested()) return; // There's no mechanism for skipping the remaining projects
if (searchedProjects.has(getProjectKey(project))) return; // Can loop forever without this (enqueue here, dequeue above, repeat)
if (resultsMap.has(project)) return; // Can loop forever without this (enqueue here, dequeue above, repeat)
const location = mapDefinitionInProject(defaultDefinition, project, getGeneratedDefinition, getSourceDefinition);
if (location) {